2 log 2x 1 8

$2 log 2x 1 8. Log12(x2-4x-1)=-2. log5 x 2 2x log5 x 2 +10. log2(1+x)=log2(1-x)+2. (х+5)log5 (х+2)=2(х+4)log5(х+2) ответ.$

$2 log 2x 1 8. Log x 8=-34 решение. log2x-log3x=5. вычислить log5 125 решение. log 0.2 (x-2)-log0.2(4-x)>log0.2 1.5.$

$2 log 2x 1 8. Log2 0,5 4x + log2 x 2 8 = 8, [0; 2). log2(9 − 0,5х) = 2. ( log_{0.5} х)^2 - log_{0.5} (x^2) >3. log8 x 5 log8 2x-2.$

$2 log 2x 1 8. Log2 5-xx-8+log0.5 x-5 log12 x-8 2. log2 8x log0 125 x 2 log0.5x16 14. log2 x 2 4 log0.5 0.5x. log 0,2 (16x2+8) log (x2+1).$

$2 log 2x 1 8. (2*0,5^x+2 -0,5*2^x+2)(2log. log0.5(x^2-x)>=-1. ( log_{0.5} х)^2 - log_{0.5} (x^2) >3. лог 0.5 (3x+1)= -2.$